問題描述

我正在遠離 mysql 和 mysqli，因為 stackoverflow 上的許多用戶一直在說好話.

I'm moving away from mysql and mysqli as many users on stackoverflow are constantly saying good things about it.

我制作了一個數據庫類并對此進行了測試，這可以很好地連接到數據庫.我試圖更新我準備好的語句以匹配但是我在陌生的領域并最終收到以下錯誤:

I've made a database class and have tested this, this connects fine to the database. I've tried to update my prepared statements to match however I am in unfamiliar territory and have ended up getting the following error:

Fatal error: Call to undefined method PDOStatement::bind_param() in E:xampphtdocsimanageinsert.php on line 50

這反映了這一行:

$stmt->bind_param("s", $_POST['email']);

另外，關于這個，我得到了數據庫連接成功和關閉語句返回給我以及致命錯誤，例如:

Also in regards to this I am getting the database connection success and close statements returned to me as well as the fatal error e.g:

連接數據庫成功！連接數據庫成功！斷開數據庫連接成功！

我將解釋我想要實現的目標:

I'll explain what I am trying to achieve:

• 在注冊用戶之前檢查數據庫中是否存在電子郵件
• 如果是，請告訴用戶此電子郵件存在
• 如果不匹配，則將用戶插入到用戶表中并加密密碼

相關代碼如下，如果有人能給我一些指導，我將不勝感激.

The relevant code is below and would appreciate if anyone could give me some guidance on this.

index.php

        <form id="loginForm" method="POST" action="class.Login.php">
        <input type="text" id="email" name="email" placeholder="E-mail">
        <input type="password" id="password" name="password" placeholder="Password" class="showpassword"> 
        <input type="submit" name="submit" value="Log in"></form>

插入.php

public function insert() {

                    $stmt = $this->pdo->prepare("SELECT COUNT(*) FROM users WHERE email=?");
                    $stmt->bind_param("s", $_POST['email']);
                    $stmt->execute();
                    $stmt->bind_result($email_count);
                    $stmt->fetch();//fecth
                    $stmt->close();     

                    if ($email_count > 0) {
                        echo "email exisits! click here to try <a href='register'>again</a>";
                        } else {
                            //escape the POST data for added protection
                            $username = isset($_POST['username']) ? $_POST['username'] : null;
                            $cryptedPassword = crypt($_POST['password']);
                            $password = $cryptedPassword;
                            $name = isset($_POST['name']) ? $_POST['name'] : null;
                            $email = isset($_POST['email']) ? $_POST['email'] : null;
                            $stmta = $this->pdo->prepare("INSERT INTO users (username, password, name, email) VALUES (?, ?, ?, ?)");
                            //var_dump($this->pdo->error);
                            $stmta->bind_param('ssss', $username, $password, $name, $email); // bind strings to the paramater

                                /* execute prepared statement */
                                $stmta->execute();
                                printf("%d Row inserted.
", $stmta->affected_rows);
                                /* close statement and connection */
                                $stmta->close();
                } // end email_count and insert to table
            } // end function

connect/class.Database.php

connect/class.Database.php

<?php

// Database connection PDO

class Database {

    public function __construct() {
        // Connection information
        $host   = 'localhost';
        $dbname = 'imanage';
        $user   = 'root';
        $pass   = '';

        // Attempt DB connection
        try
        {
            $this->pdo = new PDO("mysql:host=$host;dbname=$dbname", $user, $pass);
            $this->pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
            echo 'Successfully connected to the database!';
        }
        catch(PDOException $e)
        {
            echo $e->getMessage();
        }

    }

     public function __destruct()
    {
        // Disconnect from DB
        $this->pdo = null;
        echo 'Successfully disconnected from the database!';
    }


}

$run = new Database();
?>

推薦答案

一些 PDO 示例

綁定參數示例

$stmt = $this->pdo->prepare("SELECT COUNT(*) FROM users WHERE email=:email");
$stmt->bindParam(":email", $_POST['email']);
$stmt->execute();
$stmt->fetch(PDO::FETCH_ASSOC);

數組示例

$data = array($username, $password, $name, $email); 
$stmta = $this->pdo->prepare("INSERT INTO users (username, password, name, email) VALUES (?, ?, ?, ?)");
$stmta->execute($data);

PDO教程

這篇關于PDO bind_param 是未定義的方法的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！