問題描述

我已將 MySQL 表的結果輸出到 HTML 表.在最后一列中，我想添加一個刪除選項，它調用另一個表單并刪除用戶.我似乎無法讓它工作.

I have outputted the results of a MySQL table to an HTML table. In the last column, I want to add a delete option which calls another form and deletes the user. I can't seem to get it to work though.

這是我的結果頁面代碼:

This is my code for the results page:

<?php

    $contacts = mysql_query("
        SELECT * FROM contacts ORDER BY ID ASC") or die( mysql_error() );

    // If results
    if( mysql_num_rows( $contacts ) > 0 )
    ?>

    <table id="contact-list">
        <thead>
            <tr>
                <th>Name</th>
                <th>Email</th>
                <th>Telephone</th>
                <th>Address</th>
  <th>Delete</th>
            </tr>
        </thead>
        <tbody>

        <?php while( $contact = mysql_fetch_array( $contacts ) ) : ?>



            <tr>
                <td class="contact-name"><?php echo $contact['name']; ?></td>
                <td class="contact-email"><?php echo $contact['email']; ?></td>
                <td class="contact-telephone"><?php echo $contact['telephone']; ?></td>
                <td class="contact-address"><?php echo $contact['address']; ?></td>
                <td class="contact-delete"><form action='delete.php' method="post">
<input type="hidden" name="name" value="">
<input type="submit" name="submit" value="Delete">
</form></td>                
            </tr>

        <?php endwhile; ?>

        </tbody>
    </table>

而且，這是我的 delete.php 腳本

and, this is my delete.php script

<?php

//Define the query
$query = "DELETE FROM contacts WHERE name={$_POST['name']} LIMIT 1";

//sends the query to delete the entry
mysql_query ($query);

if (mysql_affected_rows() == 1) { 
//if it updated
?>

            <strong>Contact Has Been Deleted</strong><br /><br />

<?php
 } else { 
//if it failed
?>

            <strong>Deletion Failed</strong><br /><br />


<?php
} 
?>

很確定我只是遺漏了一些東西，但我不知道那是什么:(

Pretty sure I'm just missing something, but I can't figure out what that is :(

推薦答案

您必須在刪除鏈接中傳遞變量.你必須通過 <?php echo $contact['name'];?> 隱藏字段中的名稱值或在 URL

You have to pass variable in delete link. You must have to pass <?php echo $contact['name']; ?> name value in hidden field or pass this value in URL

替換

<td class="contact-delete">
      <form action='delete.php' method="post">
      <input type="hidden" name="name" value="">
      <input type="submit" name="submit" value="Delete">
      </form>
</td>

隨著

<td class="contact-delete">
    <form action='delete.php?name="<?php echo $contact['name']; ?>"' method="post">
        <input type="hidden" name="name" value="<?php echo $contact['name']; ?>">
        <input type="submit" name="submit" value="Delete">
    </form>
</td>

這篇關于將刪除按鈕添加到 PHP 結果表的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！