問題描述

我有多個使用靜態方法的類.這些函數使用

I have multiple classes that use static methods. These functions connect to the database using

$mysqli = new mysqli(DB_SERVER, DB_USER, DB_PASS, DB_NAME);

其中常量 DB_SERVER、DB_USER、DB_PASS、DB_NAME 是在全局可訪問文件中定義的數據庫變量.最近，我的網站開始變慢，在分析腳本后，我意識到創建對象 ($mysqli) 的調用導致了這個問題.

where the constants DB_SERVER, DB_USER, DB_PASS, DB_NAME are database variables defined in a globally accessible file. Recently, my site started becoming slow and after profiling the script I realized that the call to create the object($mysqli) was causing this problem.

我的大部分類都從 mysqli 擴展，使得

Most of my classes extend from mysqli such that

public function __construct($user_id) {
    parent::__construct(DB_SERVER, DB_USER, DB_PASS, DB_NAME);
    $this->retrieve_user_details($user_id);
    $this->check_user_account_type();

}

據我所知，靜態方法不要使用 __construct 方法.

It is to my understanding that static methods DO NOT use the __construct method.

有人可以指導我如何創建 $mysqli 對象，以便所有需要它的靜態方法都可以訪問它.

Could someone guide me on how I can create the $mysqli object once such that it can be accessed by all static methods that require it.

推薦答案

這是一種方法:

創建一個可以從任何地方靜態訪問的單例類.

Create a singleton class, that can be accessed statically from anywhere.

class DBConnector {
    private static $instance ;
    public function __construct($host, $user, $password, $db){
      if (self::$instance){
        exit("Instance on DBConnection already exists.") ;
      }
    }

    public static function getInstance(){
      if (!self::$instance){
        self::$instance = new DBConnector(a,b,c,d) ;
      }
      return $instance ;
    }
}

一個例子是:

$mysqli = DBConnector::getInstance() ;

但是我建議也使用另一種解決方案:

$mysqli = new MySQLi(a,b,c,d) ;

然后你可以將該對象傳遞給其他類(構造函數)

Then you could pass that object to other classes (constructor)

class Shop {
  private $mysqli ;
  public function __construct(MySQLi $mysqli){
    $this->mysqli = $mysqli ;
  }
}

$show = new Shop($mysqli) ;

這篇關于創建一個全局可訪問的 MySQLi 對象的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！