問題描述
我一直在閱讀有關此功能的信息:.真的很有幫助.
如果您的表單只有來自單個模型的字段，則您的更新方法可能非常簡單，如下所示:
公共函數更新($id){$user = User::find($id);if (!$user->update(Input::all())) {返回重定向::返回()->with('message', '保存模型時出錯')->withInput();}return Redirect::route('user.saved')->with('message', '用戶更新.');}對于稍微復雜一點的表單，編碼人員將不得不向他們的控制器添加更多邏輯，如果您進行更多研究，我認為您可以做到這一點:
公共函數更新($id){$user = User::find($id);$inputs = Input::all();如果 (!$user->update($inputs)) {$address = new UserAddress($inputs['address']);$user->address()->save($address);...}...}I've been reading about this feature: http://laravel.com/docs/html#form-model-binding
And it looks really neat, but there are couple of things that I'm not certain about.
Do I need to put any code in the controller action to process this form? What does that look like?
The model (User) I want to bind in my form has a separate table for addresses. So I want to be able to fill out the User model's fields, but also the fields for the related Address model. Can I do that with form-model-binding, or do I have to handle the form manually?
Or, failing that, can I use form model binding for the user fields, but manually handle the address fields?
You don't need any different code in your controller to process this form. All your (named) form variables will be in Input::all().
The model ($user) you pass in
Form::model($user, array('route' => array('user.update', $user->id)))
Is just any record you need to, if you have more than one table involved, you'll have to do something like
$user = User::where('id',$userID)
->leftJoin('users_addresses', 'users_addresses.user_id', '=', 'users.id')
->first();
And pass this composed model to your Form::model().
How you name your inputs is entirely up to you, because you'll have to write the logic to process your form. But, in my opinion users_address[street] for the address inputs is good, because you'll end up with an array of addresses columns that you can pass right away to your UserAddress model.
<html>
<head>
<title></title>
</head>
<body>
{{ Form::model($user, array('route' => array('user.update', $user->id))) }}
{{ Form::label('first_name', 'First Name:', array('class' => 'address')) }}
{{ Form::text('first_name') }}
{{ Form::label('last_name', 'Last Name:', array('class' => 'address')) }}
{{ Form::text('last_name') }}
{{ Form::label('email', 'E-Mail Address', array('class' => 'address')) }}
{{ Form::text('email') }}
{{ Form::label('address[street1]', 'Address (Street 1)', array('class' => 'address')) }}
{{ Form::text('address[street1]') }}
{{ Form::label('address[street2]', 'Address (Street 2)', array('class' => 'address')) }}
{{ Form::text('address[street2]') }}
{{ Form::label('ddress[city]', 'City', array('class' => 'address')) }}
{{ Form::text('address[city]') }}
{{ Form::label('address[state]', 'State', array('class' => 'address')) }}
{{ Form::text('address[state]') }}
{{ Form::label('address[zip]', 'Zip Code', array('class' => 'address')) }}
{{ Form::text('address[zip]') }}
{{ Form::submit('Send this form!') }}
{{ Form::close() }}
</body>
</html>
And if you do dd( Input::all() ) in your controller, you'll get something like this:
This result is provided by Kint's dd(): https://github.com/raveren/kint. Really helpful.
If your form just have fields from a single Model, your update method can be very simple and look something like:
public function update($id)
{
$user = User::find($id);
if (!$user->update(Input::all())) {
return Redirect::back()
->with('message', 'Something wrong happened while saving your model')
->withInput();
}
return Redirect::route('user.saved')
->with('message', 'User updated.');
}
On forms a little bit more complex, coders will have to add more logic to their controllers, in you case with a little bit more of research I think you can make this happen:
public function update($id)
{
$user = User::find($id);
$inputs = Input::all();
if (!$user->update($inputs)) {
$address = new UserAddress($inputs['address']);
$user->address()->save($address);
...
}
...
}
這篇關于Laravel 表單模型綁定的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！