問題描述

我有一個與 這個不同的問題.場景相同，但我需要對結果進行更多過濾.

I have a different problem from this. The scenario is same but I am in need of more filtration of the results.

讓我解釋一下.

考慮我有 2 張桌子

車輛

 id
 name
 staff_id
 distance
 mileage

員工

 id
 name
 designation

我只想從兩個表(模型)中選擇 id 和 name.Vehicle Model 包含與 Staff 模型的 belongsTo 關系.

I want to select only id and name from both tables(Models). The Vehicle Model contain a belongsTo relation to Staff model.

class Vehicle extends Model
{
    public function staff()
    {
      return $this->belongsTo('AppStaff','staff_id');
    }
}

我加入使用這個

Vehicle::where('id',1)
            ->with(['staff'=> function($query){
                            // selecting fields from staff table
                            $query->select(['staff.id','staff.name']);
                          }])
            ->get();

當我像這樣將字段放在 ->get() 中時

When I put fields in ->get() like this

->get(['id','name'])

它過濾了vehicle表，但沒有產生Staff表的結果.

it filters the vehicle table but produce no result of Staff table.

有什么想法嗎?

推薦答案

終于找到了..在 ->get() 中，你必須像這樣輸入 'staff_id'

Finally found it.. In the ->get() you have to put the 'staff_id' like this

Vehicle::where('id',1)
            ->with(['staff'=> function($query){
                            // selecting fields from staff table
                            $query->select(['staff.id','staff.name']);
                          }])
            ->get(['id','name','staff_id']);

由于我沒有使用 staff_id，它無法執行連接，因此沒有顯示人員表字段.

Since I didn't take the staff_id, it couldn't perform the join and hence staff table fields were not shown.

這篇關于如何從連接表中選擇列:laravel eloquent的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！