問題描述

我有以下 php 代碼:

I have the following php code:

<?php




if (!isset($_REQUEST['search'])){

    while(($write=mysql_fetch_array($gamesearched)) != null){
    echo "Found!";
    }else{
    echo "No results";
    }

    }
?>

它給了我一個錯誤:

解析錯誤:語法錯誤，意外的else"(T_ELSE) inC:phpwwwGameplayackgame.php 第 41 行

Parse error: syntax error, unexpected 'else' (T_ELSE) in C:phpwwwGameplayackgame.php on line 41

推薦答案

在 PHP 中，while 語句不能有 else 子句.你需要在 while 之外的東西，它可以告訴你它是否至少被執行過一次.

In PHP, a while statement can't have an else clause. You need something external to the while that can tell you if it was executed at least once.

這樣的事情怎么樣?

$total = mysql_num_rows($gamesearched);
if ($total > 0) {
    while (($write=mysql_fetch_array($gamesearched)) !== false) {
        echo "Found!";
    }
} else {
    echo "No results";
}

在這種情況下，我在開始之前查找了找到的總行數，但我也可以通過將計數器設置為零然后在 while 循環內遞增它來開始.看起來像這樣:

In this case, I've looked up the total number of rows found before I start, but I could also have started by setting a counter to zero and then incrementing it inside the while loop. That would look something like this:

$total = 0;
while (($write=mysql_fetch_array($gamesearched)) !== false) {
    $total++;
    echo "Found!";
}
if ($total == 0) {
    echo "No results";
}

請注意，如果沒有更多行，mysql_fetch_array() 將返回 false，因此我也為您更新了 while 條件.

Note that mysql_fetch_array() returns false if there are no more rows, so I've updated the while condition for you as well.

綜上所述，有充分的理由不在新代碼中使用 mysql_* 函數.有關更多詳細信息和一些更好的選擇，請參閱此問題:為什么不應該我在 PHP 中使用 mysql_* 函數?

All that being said, there are good reasons not to use mysql_* functions in new code. See this question for more details, and some better alternatives: Why shouldn't I use mysql_* functions in PHP?

這篇關于PHP - While/Else 錯誤?的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！