問(wèn)題描述
我想做的是通過(guò) ajax 和 php 調(diào)用一些數(shù)據(jù)庫(kù)數(shù)據(jù).但是ajax調(diào)用不起作用，網(wǎng)上也找不到解決辦法.
What I'm trying to do is calling some database data via ajax and php. But the ajax call doesn't work, and I can't find out a solution on the web.
這是我的代碼:
test.php
<?php
include_once 'db_class.php';
$cat = $_GET['cat'];
$dbconn = new dbconn('localhost', 'root', 'somepsw', 'blog');
$dbconn->set_query("select * from posts where category = '".$cat."'");
echo '<br/>'.$dbconn->query.'<br/>';
$result = $dbconn->result;
$num = $dbconn->num_results;
$array = mysqli_fetch_assoc($result);
echo json_encode($array);
?>
如果我在瀏覽器上輸入那個(gè)網(wǎng)址:http://127.0.0.1:82/blog/ws/test.php?cat=css
If i type that url on browser: http://127.0.0.1:82/blog/ws/test.php?cat=css
jsonEncode 返回的數(shù)據(jù)是正確的，但是當(dāng)我用 jquery 在 html 頁(yè)面上加載它時(shí)，他無(wú)法讀取數(shù)據(jù).
The data returned via jsonEncode is correct, but when i'm loading it on a html page with jquery he can't read the data.
test.html
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<script>
function ajaxCall() {
var css;
$.ajax({
url: 'test.php',
type: "GET",
data: {cat: css},
dataType: 'json',
success: function(rows)
{
alert(rows);
},
error: function() { alert("An error occurred."); }
});
}
ajaxCall();
</script>
</head>
<body></body>
</html>
提前致謝.
推薦答案
你的變量 css 沒(méi)有價(jià)值.您想使用 string 'css'.也許您也希望能夠加載其他類(lèi)別.因此，將您的 ajaxCall 函數(shù)更改為
Your variable css has no value. You wanted to use the string 'css'. Maybe you want to be able to load other categories, too. So change your ajaxCall function to
function ajaxCall(category)
{
$.ajax({
url: 'test.php',
type: "GET",
data: {cat: category},
dataType: 'json',
success: function(rows) {
alert(rows);
},
error: function() {
alert("An error occurred.");
}
});
}
并使用
ajaxCall('css');
這篇關(guān)于通過(guò)ajax調(diào)用加載mysqli php數(shù)據(jù)的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，也希望大家多多支持html5模板網(wǎng)！