問題描述

這個(gè)問題已經(jīng)出現(xiàn)了好幾次，我已經(jīng)閱讀了所有的答案，但我還沒有看到一個(gè)真正可靠的方法來處理這個(gè)問題.在我的解決方案中，我使用從調(diào)用 Activity 到 AlertDialog 的偵聽器，如下所示:

This question has come up several times and I've read all the answers, but I haven't seen a truly robust way to handle this. In my solution, I am using listeners from the calling Activity to the AlertDialog like so:

public class MyDialogFragment extends DialogFragment {

    public interface MyDialogFragmentListener {
        public void onReturnValue(String foo);
    }

    public void init(boolean someValue)
    {
        sSomeValue = someValue;
        listeners = new ArrayList<MyDialogFragmentListener>();
    }
    static boolean sSomeValue;
    private static ArrayList<MyDialogFragmentListener> listeners;

    public void addMyDialogFragmentListener(MyDialogFragmentListener l)
    {
        listeners.add(l);
    }

    public void removeMyDialogFragmentListener(MyDialogFragmentListener l)
    {
        listeners.remove(l);
    }

    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState) {
        AlertDialog.Builder builder = new AlertDialog.Builder(getActivity());
        builder.setTitle(R.string.title)
           .setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() {
               @Override
               public void onClick(DialogInterface dialog, int id) {
                   for (MyDialogFragmentListener listener : listeners) {
                       listener.onReturnValue("some value");
                   }
               }
           })
           .setNegativeButton(R.string.cancel, new DialogInterface.OnClickListener() {
               public void onClick(DialogInterface dialog, int id) {
                   // User cancelled the dialog
                   // Nothing to do but exit
               }
           });
        if (sSomeValue) {
            builder.setMessage(R.string.some_value_message);
        } else {
            builder.setMessage(R.string.not_some_value_message);
        }
        // Create the AlertDialog object and return it
        return builder.create();
    }
}

然后在調(diào)用Activity中，我正常實(shí)例化對(duì)象，通過init傳入任何參數(shù)并設(shè)置我的監(jiān)聽器.

Then in the calling Activity, I instantiate the object normally, pass in any arguments through init and set my listener.

問題出在:當(dāng)您在對(duì)話框打開時(shí)旋轉(zhuǎn)設(shè)備并更改方向時(shí)，Activity 和 MyDialogFragment 對(duì)象都會(huì)重新創(chuàng)建.為了確保輸入值不會(huì)搞砸，我將初始化值設(shè)置為 static.這對(duì)我來說感覺很奇怪，但由于一次只會(huì)有一個(gè)這樣的對(duì)話，我可以接受.問題出在返回值上.原始偵聽器將被調(diào)用.這很好，因?yàn)樵搶?duì)象仍然存在，但如果需要更新 Activity 上的 UI(存在)，它不會(huì)被更新，因?yàn)?newActivity 實(shí)例現(xiàn)在正在控制 UI.

Here's the problem: when you rotate the device and change orientation while the dialog is open, both the Activity and MyDialogFragment objects get re-created. To ensure that the input values don't get screwed up, I am setting my initialized values as static. This feels hacky to me, but since there will only be one such dialog at a time, I am ok with it. Where the problem comes in is with the return value. The original listener will get called. That's fine because the object still exists, but if there is a requirement to update the UI on the Activity (which there is), it won't get updated because the new Activity instance is now controlling the UI.

我正在考慮的一個(gè)解決方案是將對(duì)話框類中的 getActivity() 強(qiáng)制轉(zhuǎn)換為我的 Activity 并強(qiáng)制對(duì)話框本身添加偵聽器，而不是調(diào)用 <代碼>活動(dòng)做.但這感覺就像是黑客的滾雪球.

One solution I am considering is casting getActivity() in the dialog class to my Activity and forcing the dialog itself to add a listener, rather than having the calling Activity do it. But this just feels like a snowballing of hacks.

優(yōu)雅地處理這個(gè)問題的最佳做法是什么?

What is the best practice for handling this gracefully?

推薦答案

你在正確的軌道上，我按照Android 開發(fā)者 - 使用 DialogFragments 文章.

You are on the right track, I follow the method recommended by the Android Developers - Using DialogFragments article.

您創(chuàng)建 DialogFragment 并定義 Activity 將實(shí)現(xiàn)的接口，就像您在上面所做的那樣:

You create your DialogFragment and define an interface that the Activity will implement, like you have done above with this:

public interface MyDialogFragmentListener {
    public void onReturnValue(String foo);
}

然后在DialogFragment中，當(dāng)你想將結(jié)果返回給Activity時(shí)，你將Activity投射到界面中:

Then in the DialogFragment when you want to return the result to the Activity you cast the activity to the interface:

@Override
public void onClick(DialogInterface dialog, int id) {
    MyDialogFragmentListener activity = (MyDialogFragmentListener) getActivity();
    activity.onReturnValue("some value");
}

然后在 Activity 中實(shí)現(xiàn)該接口并獲取值:

Then in the Activity you implement that interface and grab the value:

public class MyActivity implements MyDialogFragmentListener {
    ...
    @Override
    public void onReturnValue(String foo) {
        Log.i("onReturnValue", "Got value " + foo + " back from Dialog!");
    }
}

這篇關(guān)于在Android上將值從Dialog傳回Activity的可靠方法?的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，也希望大家多多支持html5模板網(wǎng)！