問題描述
我寫了這段代碼:
float b = 3.6;我明白了:
<上一頁>錯誤:未解決的編譯問題:類型不匹配:無法從 double 轉(zhuǎn)換為 float為什么?float的定義是什么?
在 Java 中，當(dāng)您鍵入一個十進(jìn)制數(shù)為 3.6 時，它會被解釋為一個 double.double 是 64 位精度的 IEEE 754 浮點，而 float 是 32 位精度的 IEEE 754 浮點.由于 float 不如 double 精確，因此無法隱式執(zhí)行轉(zhuǎn)換.
如果你想創(chuàng)建一個浮點數(shù)，你應(yīng)該以 f 結(jié)束你的數(shù)字(即:3.6f).
更多解釋請參見Java教程的原始數(shù)據(jù)類型定義.
I wrote this code:
float b = 3.6;
and I get this:
Error:Unresolved compilation problem:
Type mismatch: cannot convert from double to float
Why? Whats the definition of float?
In Java, when you type a decimal number as 3.6, its interpreted as a double. double is a 64-bit precision IEEE 754 floating point, while floatis a 32-bit precision IEEE 754 floating point. As a float is less precise than a double, the conversion cannot be performed implicitly.
If you want to create a float, you should end your number with f (i.e.: 3.6f).
For more explanation, see the primitive data types definition of the Java tutorial.
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