問題描述

我正在嘗試將字節(jié)值轉(zhuǎn)換為二進(jìn)制以進(jìn)行數(shù)據(jù)傳輸.基本上，我在字節(jié)數(shù)組中以二進(jìn)制形式(10101100")發(fā)送一個(gè)像AC"這樣的值，其中10101100"是一個(gè)字節(jié).我希望能夠接收這個(gè)字節(jié)并將其轉(zhuǎn)換回10101100".到目前為止，我根本沒有成功，真的不知道從哪里開始.任何幫助都會(huì)很棒.

I am trying to convert a byte value to binary for data transfer. Basically, I am sending a value like "AC" in binary ("10101100") in a byte array where "10101100" is a single byte. I want to be able to receive this byte and convert it back into "10101100." As of now I have no success at all dont really know where to begin. Any help would be great.

編輯:抱歉，我沒有意識(shí)到我忘了添加具體細(xì)節(jié).

edit: sorry for all the confusion I didnt realize that I forgot to add specific details.

基本上我需要使用字節(jié)數(shù)組通過套接字連接發(fā)送二進(jìn)制值.我可以這樣做，但我不知道如何轉(zhuǎn)換這些值并使它們正確顯示.這是一個(gè)例子:

Basically I need to use a byte array to send binary values over a socket connection. I can do that but I dont know how to convert the values and make them appear correctly. Here is an example:

我需要發(fā)送十六進(jìn)制值 ACDE48 并能夠?qū)⑵浣忉尰貋?根據(jù)文檔，我必須通過以下方式將其轉(zhuǎn)換為二進(jìn)制:byte [] b={10101100,11011110,01001000}，其中數(shù)組中的每個(gè)位置都可以保存 2 個(gè)值.然后，我需要在發(fā)送和接收這些值后將它們轉(zhuǎn)換回來.我不知道該怎么做.

I need to send the hex values ACDE48 and be able to interpret it back. According to documentation, I must convert it to binary in the following way: byte [] b={10101100,11011110,01001000}, where each place in the array can hold 2 values. I then need to convert these values back after they are sent and received. I am not sure how to go about doing this.

推薦答案

String toBinary( byte[] bytes )
{
    StringBuilder sb = new StringBuilder(bytes.length * Byte.SIZE);
    for( int i = 0; i < Byte.SIZE * bytes.length; i++ )
        sb.append((bytes[i / Byte.SIZE] << i % Byte.SIZE & 0x80) == 0 ? '0' : '1');
    return sb.toString();
}

byte[] fromBinary( String s )
{
    int sLen = s.length();
    byte[] toReturn = new byte[(sLen + Byte.SIZE - 1) / Byte.SIZE];
    char c;
    for( int i = 0; i < sLen; i++ )
        if( (c = s.charAt(i)) == '1' )
            toReturn[i / Byte.SIZE] = (byte) (toReturn[i / Byte.SIZE] | (0x80 >>> (i % Byte.SIZE)));
        else if ( c != '0' )
            throw new IllegalArgumentException();
    return toReturn;
}

也有一些更簡單的方法來處理這個(gè)問題(假設(shè)大端).

There are some simpler ways to handle this also (assumes big endian).

Integer.parseInt(hex, 16);
Integer.parseInt(binary, 2);

和

Integer.toHexString(byte).subString((Integer.SIZE - Byte.SIZE) / 4);
Integer.toBinaryString(byte).substring(Integer.SIZE - Byte.SIZE);

這篇關(guān)于在Java中將字節(jié)轉(zhuǎn)換為二進(jìn)制的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，也希望大家多多支持html5模板網(wǎng)！