問題描述

我正在嘗試修復這段代碼，我正在從具有車牌號和所有者列表(該格式)的哈希圖中打印.我試圖通過 printOwners(); 打印出所有者.但我不能讓它不打印重復.

I'm trying to fix this piece of code where I'm printing from a hashmap having a list of plate numbers and owners (that format). I'm trying to print out just the owners via printOwners(); but I can't get it to not print duplicates.

我已經玩了一段時間了，似乎無法跳過重復項.

I've played around with it for a while, just can't seem to skip over duplicates.

這是我的代碼:

import java.util.ArrayList;
import java.util.HashMap;

public class VehicleRegister {

    private HashMap<RegistrationPlate, String> owners;

    public VehicleRegister() {
        owners = new HashMap<RegistrationPlate, String>();
    }

    public boolean add(RegistrationPlate plate, String owner) {
        //search for existing plate
        if (!(owners.containsKey(plate))) { // add if no plate
            owners.put(plate, owner);
            return true;
        }

        //if plate is found, check for owner
        else if (owners.keySet().equals(owner)) {
           return false;
        }

        return false;
    }

    public String get(RegistrationPlate plate) {
        return owners.get(plate);
    }

    public boolean delete(RegistrationPlate plate) {
        if (owners.containsKey(plate)) {
            owners.remove(plate);
            return true;
        }

        return false; 
    }

    public void printRegistrationPlates() {
        for (RegistrationPlate item : owners.keySet()) {
            System.out.println(item);
        }
    }

    public void printOwners() {

        for (RegistrationPlate item : owners.keySet()) {
            System.out.println(owners.get(item));            
        }
    }
}

推薦答案

要刪除重復項，請使用 HashSet:

To remove the duplicates, use a HashSet<String>:

public void printOwners() {
    for (String s : new HashSet<>(owners.values())) {
        System.out.println(s);            
    }
}

或者使用 Java 8 Stream 和 distinct() 方法:

Alternatively with Java 8 Stream and the distinct() method:

public void printOwners() {
    owners.values().stream().distinct().forEach(System.out::println);
}

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