本文介紹了SQL - 選擇分組行的一個實例的處理方法,對大家解決問題具有一定的參考價值,需要的朋友們下面隨著小編來一起學習吧!
問題描述
我有一個對行進行分組的查詢.產品 ID 相同但日期和數量不同的多行被分組,以便我可以計算數量、平均價格等的總和.
I have a query where rows are grouped. Multiple rows where the product ID are the same but where date and quantity differs, are grouped so I can calculate the sum of quantities, average prices, etc.
我現在需要添加上次銷售的日期和相應的數量.日期加了MAX(date),怎么加對應的數量?
I now need to add the date when the last sale occurred and the corresponding quantity. I added the date with MAX(date), but how do I add the corresponding quantity?
我使用 MS SQL Server Management Studio.
I use MS SQL Server Management Studio.
示例查詢:
SELECT id,
SUM(quantity) as 'Total q',
AVG(price) as 'Avg price',
MAX(price) as 'Max price',
MAX(date) as 'Last sale date'
FROM table
WHERE date > 2018
GROUP BY id
原始樣本數據:
id quantity price date
1 20 2.30 2018-6-2
1 10 2.40 2018-6-4
1 5 2.55 2018-6-10
2 15 12.50 2018-5-20
2 100 7.50 2018-6-1
2 50 10.00 2018-6-12
預期結果:
id total q avg price max price last sale last q last p
1 35 2.42 2.55 2018-6-10 5 2.55
2 165 10.00 12.50 2018-6-12 50 10.00
推薦答案
你可以使用窗口函數
:
SELECT DISTINCT id,
SUM(quantity) OVER(PARTITION BY id) as "Total q",
AVG(price) OVER(PARTITION BY id) as "Avg price",
MAX(price) OVER(PARTITION BY id) as "Max price",
MAX(_date) OVER(PARTITION BY id) as "Last sale date",
FIRST_VALUE(quantity) OVER(PARTITION BY id ORDER BY _date DESC) AS last_q,
FIRST_VALUE(price) OVER(PARTITION BY id ORDER BY _date DESC) AS last_p
FROM tab
WHERE _date > '2018-01-01';
輸出:
┌────┬─────────┬───────────┬───────────┬─────────────────────┬────────┬────────┐
│ id │ Total q │ Avg price │ Max price │ Last sale date │ last_q │ last_p │
├────┼─────────┼───────────┼───────────┼─────────────────────┼────────┼────────┤
│ 1 │ 35 │ 2.416666 │ 2.55 │ 10/06/2018 00:00:00 │ 5 │ 2.55 │
│ 2 │ 165 │ 10.000000 │ 12.50 │ 12/06/2018 00:00:00 │ 50 │ 10.00 │
└────┴─────────┴───────────┴───────────┴─────────────────────┴────────┴────────┘
DBFiddle 演示
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