問(wèn)題描述

正如 Eric Lippert 在 這篇文章，try/catch 子句中不允許yield return.

As Eric Lippert described in this article, yield return is not allowed within try/catch clauses.

有沒(méi)有一種很好的方法可以讓我得到這樣的東西，而不必手動(dòng)編寫(xiě)自己的IEnumerator:

Is there a nice way I could get something like this, without having to write my own IEnumerator by hand:

public IEnumerable<Data> GetData()
{
    var transaction = Session.BeginTransaction());
    try 
    {
        IQuery q = CreateQuery(session);

        foreach (var result in q.Enumerable())
            yield return ProjectResult(result);  // <-- doesn't work

        session.Commit();
    }
    catch (Exception ex)
    {
        transaction.Rollback();
        throw;
    }
    finally
    {
        transaction.Dispose();
    }
}

推薦答案

我只是像這樣更改事務(wù)處理邏輯:

I'd just change the transaction-handling logic like this:

public IEnumerable<Data> GetData()
{
    var transaction = Session.BeginTransaction();
    bool rollback = true;
    try 
    {
        IQuery q = CreateQuery(session);

        foreach (var result in q.Enumerable())
        {
            yield return ProjectResult(result);
        }

        rollback = false;
        session.Commit();
    }
    finally
    {
        if (rollback)
        {
            transaction.Rollback();
        }
        transaction.Dispose();
    }
}

或者，如果您的事務(wù)支持除非已提交，否則處理意味著回滾"的想法:

Or if your transaction supports the idea of "dispose means rollback unless it's commited":

public IEnumerable<Data> GetData()
{
    using (var transaction = Session.BeginTransaction();
    {
        IQuery q = CreateQuery(session);

        foreach (var result in q.Enumerable())
        {
            yield return ProjectResult(result);
        }

        // Commits the tnrasaction, so disposing it won't roll it back.
        session.Commit();
    }
}

這篇關(guān)于try/catch 塊的收益回報(bào)的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，也希望大家多多支持html5模板網(wǎng)！